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가입일: 2022년 5월 15일

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Dt00 Iimg Pes 2013rar filile



 


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I want to get this kind of content by scraping website. I was trying to use this code import lxml.html import lxml.etree as et import urllib.request import urllib.parse url = "" response = urllib.request.urlopen(url) root = et.parse(response) rows = root.xpath("//table[@class='viewport']//tr") for row in rows: cells = row.xpath("td") print("Title: {}".format(cells[0].text_content())) For me the output is always the same Title: Dt00 I.img Pes 2013.rar Title: Dt00 I.img Pes 2013.rar Title: Dt00 I.img Pes 2013.rar Title: Dt00 I.img Pes 2013.rar Title: Dt00 I.img Pes 2013.rar I wanted to get this content Title: Dt00 I.img Pes 2013.rar Title: Dt00 E.img Pes 2013.rar Title: Dt00 E.img Pes 2013.rar Title: Dt00 E.img Pes 2013.rar Title: Dt00 E.img Pes 2013.rar I need to scrape the tables but i want to store the table content not the url. A: Here's the solution. I used BeautifulSoup. from bs4 import BeautifulSoup import requests import urllib.request url = "" response = requests.get(url) soup = BeautifulSoup(response.content,'lxml') tables = soup.find_all('table', attrs={"class": "viewport"}) for table in tables: print(table.contents[0]) Result: Dt00 I.img Pes 2013.rar Dt00 E.img Pes 2013.rar Dt00 E.img Pes 2013.rar Dt00 E.img Pes 2013.rar I

 

 

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Dt00 Iimg Pes 2013rar filile

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